Question

Find the vertical asymptotes, if any, of the graph of the rational function.

g(x) = x/x^2-16

Answer 1

\[g(x)=\frac{x}{x^2-16}\]
To find the vertical asymptote, we set the denominator equal to zero and solve for x.

x^2-16=0

Answer 2

I'm assuming that your function is\[g(x)=\frac{ x }{ x ^{2}-16 }\]

If that's true, follow tomhue's advice, set the den. = to 0, and solve for the 2 values of x that represent the solution of that equation;

Write your answers in the form x=a and x=b.

The results are the equations of your vertical asymptotes.

Answer 3

im honestly rearded at this I need the results
:/

Answer 4

retarded

Answer 5

x^2 -16 = 0
We can use algebra to isolate x.

x^2 -16 = 0
x^2 -16 +16 = 0 +16
x^2 = 16
sqrt(x^2) = sqrt(16)
Since we're taking a square root, we need to remember the +/- signs.
x = +/- sqrt(16)
which means
x = 4 and x = -4
are the equations of your vertical asymptotes. (x=n is a vertical line, y=n is a horizontal line.)