Question

Help Please?
Given the function f(x) = 2^x, find the value of f^−1(16).

Answer 1

@hartnn I know you helped me with something like this before, but its different. Can you help again?

Answer 2

sure

Answer 3

what have you tried already ?

Answer 4

I plugged 16 in as the x but im pretty sure that's not what you do...

Answer 5

\(2^x =16 \)

Answer 6

oh so I just do log2 on both sides?

Answer 7

you can,
but if you know \(16 = 2^{??}\)
then it would be much simpler

Answer 8

if you don't
better take log on both sides

Answer 9

what would be the simpler way?

Answer 10

\(16 = 2^4 \)
so ,in \(2^x = 16 \\ 2^x = 2^4

x= 4\)

Answer 11

\(2^x = 16 \\ 2^x = 2^4

\\x= 4\)

Answer 12

so f^-1(16)=4?
and that is much simpler lol

Answer 13

yes, it is :)

Answer 14

okay thank you again :)

Answer 15

welcome ^_^