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Mathematics 6 Online
OpenStudy (anonymous):

can someone please help!! A zero-order reaction has a constant rate of 4.90×10−4 M/s M/\rm s. If after 70.0 seconds the concentration has dropped to 4.00×10−2 M M, what was the initial concentration? -I continue to get -1.17M but the program tells me its wrong I don't know what to do know?

OpenStudy (anonymous):

So your method should have been to calculate the drop over those 70 seconds and then adding that value to the final concentration after the 70 seconds. Is that what you did?

OpenStudy (anonymous):

the program gave me this equation to use [A]=[A] 0 −rate×time

OpenStudy (anonymous):

Oops, concentrations. Okay, so that's a negative or..? Haha, I want to try and see what my answer comes out to be.

OpenStudy (anonymous):

I plugged in positive 1.17 and it wouldn't take it either. Any advise? I only have one attempt left......

OpenStudy (anonymous):

Is your unit chemical kinetics?

OpenStudy (anonymous):

What you're studying, I mean.

OpenStudy (anonymous):

This looks like a good resource. http://www.elcamino.edu/faculty/pdoucette/All-1B-CSM.pdf

OpenStudy (anonymous):

I believe it is M isn't it? It uses M/s units, and the seconds would cancel out leaving M.

OpenStudy (anonymous):

The unit of your study I mean, as in is this question a chemical kinetics question? :p

OpenStudy (anonymous):

Yes! sorry

OpenStudy (anonymous):

So then the equation says the final concentration equals the initial concentration minus rate times time elapsed, I think.

OpenStudy (anonymous):

And you're solving for [A]0 or initial concentration.

OpenStudy (anonymous):

[A]0 would be the initial concentration

OpenStudy (anonymous):

\[[A] = [A]o - (rate \times time)\] \[[A] + (rate \times time) = [A]o\] and I feel like that should work...but maybe I'm thinking too simply.

OpenStudy (anonymous):

that's what I used, and I continue getting 1.17 M

OpenStudy (anonymous):

Haha, can I see the calculation? If that's what you used, it must be right.

OpenStudy (anonymous):

the program says its incorrect for some reason what do you end up getting?

OpenStudy (anonymous):

I must be doing it completely wrong, that's why I want to see your calculation lol

OpenStudy (anonymous):

And it's not multiple choice, right?

OpenStudy (anonymous):

yes!!

OpenStudy (anonymous):

oh wait, I got it right!!!

OpenStudy (anonymous):

thanks!!!!! I understand what you did with the formula!!!

OpenStudy (anonymous):

I really appreciate your help, I spend an hour on this problem!! Thank a million!!!

OpenStudy (anonymous):

LOL, you're welcome. :'D Got the right answer?

OpenStudy (anonymous):

yes I got the right answer!!!! thank you so much

OpenStudy (anonymous):

:3 you're welcome

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