I figured out the first triangle, but how do I find the second?---> Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. C = 67°, a = 21, c = 20
Have you drawn a pic yet?
Hint: if you obtain something such as sin x = 1/2, there'd be more than just 1 solution.
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Do you recall law of sines?
Yes! I found the first triangle: A = 75.1°, B = 37.9°, b = 13.3. But how would I find the second?
Just apply the sine rule again.
How would I get sin x= 1/2? @mathmale
Would you please type out your result for sin A? sin A = ???? Then we'll continue this discussion.
A=75.13 sinA=.97
Solve for sin A. Oh...I see you already have sin A = 0.97. My point is that this equation has TWO solutions, not just one. Your first solution, I'd bet, was an angle A in the first quadrant. Note that sin A = 0.97 also has a solution in the second quadrant. Here's where a sketch just might help.
I don't get it.. :(
I don't think about the quadrants when I do these.. I just used the Law of Sines thing..
Hold. @austinL : would you care to sketch a diagram that will show the 2nd possible angle A whose sine is 0.97? If not, I'll do it myself. Thanks.
The whole point here is to realize that an equation such as sin A = 0.97 has TWO solutions, not just one.
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