Question

Write an equation of the line perpendicular to the line 5x-2y=-3 and passing through the point (2,-1)

Answer 1

It's an open question

Answer 2

first you would want to write 5x-2y=-3 in the form of y=mx+c
this will help you to find the m (sope) and we know a perpendicular line to another will have - inverse fraction for their slope.
then re-write a new y=mx+c with the new perpendicular slope then substitute x as 2 and y as -1

Answer 3

mx+c or mx+b
it is still the same because we now c or b is just a number which is the y intercept

Answer 4

I got 2x-5y-1=0

Answer 5

incorrect

Answer 6

rewrite 5x-2y=-3 in the form y=mx+b

Answer 7

oh, ok

Answer 8

2y=5x+3

Answer 9

now divide everything by 2
because we're making y the subject of the formula

Answer 10

5x+3=8

Answer 11

8/2=4

Answer 12

2y=4

Answer 13

2/2 crosses out; 4/2=2

Answer 14

y=2

Answer 15

nope

Answer 16

2y=5x+3
dividing everything by two will give
y= (5/2)x + 3/2

Answer 17

so, divide the 5x and 3 by 2 right?

Answer 18

yes

Answer 19

Thx

Answer 20

its not finished yet