Question

What is the equation in standard form of the line which passes through (4, −2) and has a slope of −3?

x + 3y = 10

x + 3y = −10

3x + y = 10

3x + y = −10

Answer 1

\(\bf \begin{array}{lllll}
&x_1&y_1\\
&({\color{red}{ 4}}\quad ,&{\color{blue}{ -2}})\quad
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= -3
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form} \)

Answer 2

x + 3y = 10

x + 3y = −10

3x + y = 10

3x + y = −10 ?? i dont get it

Answer 3

i know it would be 3x because its the slope.

Answer 4

right

Answer 5

i dont see how 10 is the answer.

Answer 6

\(\bf \begin{array}{lllll}
&x_1&y_1\\
&({\color{red}{ 4}}\quad ,&{\color{blue}{ -2}})\quad
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= -3
\\ \quad \\

y-{\color{blue}{ -2}}={\color{green}{ -3}}(x-{\color{red}{ 4}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form} \implies y+2=-3x+12\implies 3x+y=10\)

Answer 7

thank you !

Answer 8

I gather you weren't required to solve for "y", but anyway

Answer 9

yw