Question

find the formula for the graph below

Answer 1

any ideas?

Answer 2

2-4sin(3pix) ? @jdoe0001

Answer 3

hmmm what did you get for the period?

Answer 4

3pi

Answer 5

hmm well, is not \(3\pi\)

can you tell the amplitude of the function from the graph?

Answer 6

amp is 2 ..since +2=4 and -2 = 0

Answer 7

well, yes, is the sine function
it has an amplitude of "2"

it has a vertical shift upwards of 2, the "hub" went UP by 2

and it has a period of \(6\pi\)

so \(\bf y = Asin(Bx)+C\qquad
\textit{new period}=\cfrac{\textit{original period}}{B}
\\ \quad \\

{\color{blue}{ 6\pi = \cfrac{2\pi}{B}\implies B=\cfrac{2\pi}{6\pi}\implies B=\cfrac{\pi}{3}}}
\\ \quad \\
y = Asin(Bx)+C\implies y = 2sin\left(\frac{\pi}{3}x\right)+2\)

Answer 8

hmmm wait a sec.. dohh.. I kinda left the \(\pi\) there..

Answer 9

\(\bf y = Asin(Bx)+C\qquad
\textit{new period}=\cfrac{\textit{original period}}{B}
\\ \quad \\

{\color{blue}{ 6\pi = \cfrac{2\pi}{B}\implies B=\cfrac{2\pi}{6\pi}\implies B=\cfrac{1}{3}}}
\\ \quad \\
y = Asin(Bx)+C\implies y = 2sin\left(\frac{1}{3}x\right)+2\)

Answer 10

oh! i was doing it completely wrong with 2-4sin thank you!

Answer 11

yw