Question

find the angle between

Answer 1

lines (x-2)/1=(1-y)/3=Z-3/1 and x/2=y+3/-1=z-1/2

Answer 2

\[(x-2)/1=(1-y)/3=(z-3)/1\] and \[\frac{ x }{ 2 }=\frac{ y+3 }{ -1 }=\frac{ z-1 }{ 2 }\]

Answer 3

O_O It's SHinchan !

Answer 4

Ahh I don't remember how to do this? D:
Do we want to find the vectors normal to the surfaces? Oh it's a line... +_+
Hmmm

Answer 5

\[a.b=|a||b| \cos \theta\]

Answer 6

So do we want to rewrite the lines in parametric form and mess with them from there?

Answer 7

i tried to find the normal vector of them which is n1<1,3,1> and n2<2,-1,2> and used the formula but didn't work.

Answer 8

I think the normal to the first line is <1,-3,1> isn't it? :o

Answer 9

\[1) x=1+2t, y=1-3t, z=3+t\]

Answer 10

\[1) x=\color{red}{2+t}, y=1-3t, z=3+t\]

Answer 11

dang it, i messed up "<1,-3,1>" -3 that the loophole

Answer 12

thx @zepdrix

Answer 13

i got 45.3