How do I approximate left and right Riemann sum with an integral?

Question

darkigloo · Answer

$$\int\limits_{0}^{2} e^(x^2)$$
e^(x^2)

darkigloo · Answer

with two subintervals of equal length

shamil98 · Answer

you can't integrate e^x^2..

darkigloo · Answer

what??? not even with a calculator?

shamil98 · Answer

wolfram gives an imaginary error function but i doubt thats what you want..

darkigloo · Answer

the actual question is If the definite integral e^(x^2) dx from 0 to 2 is first approximated by using a left riemann sum with 2 subintervals of = width and then approximated by using trapezoidal rule with 2 = subintervals , the difference between the two approximations is..

shamil98 · Answer

n = 2,
from 0 to 2
using LRAM you can do it think.
2 subintervals so 
x = 0  , x= 1, x= 2
same thing for RRAM.. graph it i, and construct the rectangles so it's easier to see.

darkigloo · Answer

ok but is there like a formula for LRAM and RRAM? I don't know how to actually get the answer.

shamil98 · Answer

all LRAM is using rectangles to approximate the area under the curve.. LRAM = you use the left height value(y) and RRAM you use the Right height value. http://www.chaoticgolf.com/worksheets/calc/academy/notecards/lramrrammram.pdf

darkigloo · Answer

So am i supposed to find e^0 , e^1, and e^4 and add them all to get LRAM?