Question

Let R be the region bounded above by the graph of y=e^(-4x), below by the x-axis, and on the left by the y-axis. Compute the area of R and the volume of the solid obtained by revolving R about the x-axis.

Answer 1

Notice that there is no `right` boundary for the region R?
\[\Large\bf\sf \int\limits_0^? e^{-4x}\;dx\]

Answer 2

Do you understand what you'll need to use for the upper boundary to find the area?

Answer 3

you might have had a type somewhere. I don't see any bounded region

Answer 4

It should be fine :)
The function converges quickly enough.
So we just integrate from 0 to infinity and shouldn't have any problems.

Answer 5

nope I have no clue...whenever i see these problems I just blank out..

Answer 6

ohh its from 0 to infinity?

Answer 7

I used -infinity