Let R be the region bounded above by the graph of y=e^(-4x), below by the x-axis, and on the left by the y-axis. Compute the area of R and the volume of the solid obtained by revolving R about the x-axis.

Question

zepdrix · Answer

Notice that there is no `right` boundary for the region R?
$$\Large\bf\sf \int\limits_0^? e^{-4x}\;dx$$

zepdrix · Answer

Do you understand what you'll need to use for the upper boundary to find the area?

anonymous · Answer

you might have had a type somewhere. I don't see any bounded region

zepdrix · Answer

It should be fine :)
The function converges quickly enough.
So we just integrate from 0 to infinity and shouldn't have any problems.

anonymous · Answer

nope I have no clue...whenever i see these problems I just blank out..

anonymous · Answer

ohh its from 0 to infinity?

anonymous · Answer

I used -infinity

zepdrix · Answer

|dw:1393120693233:dw|