Mathematics
8 Online
OpenStudy (anonymous):
X^3 - xy + y^3= 1
Solve for dy/dx
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OpenStudy (unklerhaukus):
take the derivative term by term,
what is the derivative (with respect to x) of x^3
OpenStudy (unklerhaukus):
d/dx (x^3) = ?
OpenStudy (unklerhaukus):
[for the second two terms you will need to apply the product rule]
OpenStudy (anonymous):
i have 3x^2 - x (dy/dx) + 3y^2 dy/dx = 0
OpenStudy (unklerhaukus):
youv'e missed a term,
d/dx (xy) =x d/dx (y) + y d/dx (x)
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OpenStudy (anonymous):
ok back up is it
3x^2 - (x dy/dx + y + 1) = 3y^2 dy/dx =0
OpenStudy (anonymous):
3x^2 - (x dy/dx + y dy/dx x ) + 3y^2 dy/dx =0
OpenStudy (anonymous):
am I on the right track
OpenStudy (unklerhaukus):
*
3x^2 - (x dy/dx + y d/dx (x) ) + 3y^2 dy/dx =0
OpenStudy (unklerhaukus):
that term y d/dx (x) = y dx/dx = y (1) = y
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OpenStudy (unklerhaukus):
the other terms you have done correctly
OpenStudy (unklerhaukus):
can you see what i mean?
OpenStudy (anonymous):
yea but where do I go next
OpenStudy (unklerhaukus):
3x^2 - (x dy/dx + y) + 3y^2 dy/dx =0
now you just have to solve the equation for dy/dx by rearranging
OpenStudy (unklerhaukus):
you should end up with dy/dx = some fraction
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OpenStudy (anonymous):
i am really confused on the algebra piece of it
OpenStudy (unklerhaukus):
well expand the bracket, (bring the minus across those two terms)
OpenStudy (unklerhaukus):
tell me what you get after this step
OpenStudy (anonymous):
3x
OpenStudy (anonymous):
3x^2 - x dy/dx -y +3y^2dy/dx
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OpenStudy (anonymous):
sorry didn't realize I forgot to paste
OpenStudy (unklerhaukus):
dont forget the equals sign
OpenStudy (anonymous):
of course
OpenStudy (unklerhaukus):
3x^2 - x dy/dx -y +3y^2dy/dx = 0
now think of the dy/dx as just a variable
factor the dy/dx from two terms
OpenStudy (anonymous):
^
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OpenStudy (anonymous):
oops 3x^2 - y dy/dx ( x + 3y^2) =0
OpenStudy (unklerhaukus):
not quite
OpenStudy (anonymous):
dy/dx = (-3x^2 + y) / (x + 3y^2) = 0
OpenStudy (anonymous):
dy/dx = x/y
OpenStudy (unklerhaukus):
hmm i'm not sure how you got that but its good,
except this time it dosent equal zero
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OpenStudy (anonymous):
oops didn't mean to put that lol
OpenStudy (unklerhaukus):
dy/dx cannot be simplified to x/y, because d is not a number that can cancel, it is an operator
OpenStudy (anonymous):
ugh what am i doing wrong
OpenStudy (anonymous):
did I have it right before I tried to simply it
OpenStudy (unklerhaukus):
3x^2 - x dy/dx -y +3y^2dy/dx = 0
3x^2-y + dy/dx (-x + 3y^2) = 0
dy/dx (-x+3y^2) = y-3x^2
dy/dx = (y-3x^2) / (-x + 3y^2)
= (3x^2 -y ) / (x-3y^2)
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OpenStudy (anonymous):
thanks I don't know what I did wrong