An infinite sheet of charge, oriented perpendicular to the x-axis, passes through x = 0. It has a surface charge density σ1 = -3.9 μC/m2. A thick, infinite conducting slab, also oriented perpendicular to the x-axis occupiees the region between a = 2.2 cm and b = 4 cm. The conducting slab has a net charge per unit area of σ2 = 81 μC/m2.

1) What is Ex(P), the value of the x-component of the electric field at point P, located a distance 7.6 cm from the infinite sheet of charge? Posting the Hw with a diagram it will be the last group of problems.

Question

An infinite sheet of charge, oriented perpendicular to the x-axis, passes through x = 0. It has a surface charge density σ1 = -3.9 μC/m2. A thick, infinite conducting slab, also oriented perpendicular to the x-axis occupiees the region between a = 2.2 cm and b = 4 cm. The conducting slab has a net charge per unit area of σ2 = 81 μC/m2.

1) What is Ex(P), the value of the x-component of the electric field at point P, located a distance 7.6 cm from the infinite sheet of charge? Posting the Hw with a diagram it will be the last group of problems.

anonymous · Answer

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anonymous · Answer

This is problem is like considering 3 infinte sheet of charges right? 
the slap can be considered to be 2 thin sheets right?

anonymous · Answer

right. one is pulling the other two are pushing. When it I got the wrong answer. Don't know if I make an arithmetic mistake or a concept. hope some one here can get it.

anonymous · Answer

show your work here, ll be glad to look over and correct your mistake..!

anonymous · Answer

k=9*10^9 
Qr=charge density right =(-3.9*10^-6+81*10^-6)/2
Ql=charge density left= (81*10^-6+3.9*10^-6)/2
Qa=inf line=-3.9*10^-6
Qb=charge of conductive plate= 81*10^-6


I have made two attempts first one I think is wrong but is it is the simplest  so =2*k*(Qr+Ql+Qa)/(7.6/100)^2=240270083.102493 


=[k*Qa/(7.6/100)^2]+[k*Ql/(5.4/100)^2]+[k*Qr/(3.6/100)^2]= 392649982.045758

Both are wrong