Question

So I have a physics question: A 2.00-kg mass vibrates according to the equation x(t) = 0.650 cos 7.40 t , where x is in meters and t in seconds. Determine a) the amplitude, b) the frequency, c) the total energy, and d) the kinetic energy and potential energy when x = 0.260 m. Now I've done part a, but the other three have me confused.

Answer 1

now eqution of SHM is \[x=acos \omega t\]frequency n =1/T,and \[T=2\pi/ \omega\]
total energy\[E=\frac{ 1 }{ 2 } m \omega ^{2} a ^{2}\]
kinetic enrgy at positotion x is\[KE=\frac{ 1 }{ 2 }m \omega ^{2} (a ^{2} -x ^{2})\]
potential energy at a point x is \[PE= \frac{ 1 }{ 2 }m \omega ^{2} x ^{2}\]

Answer 2

Thank you! I have one question, does "a" equal maximum displacement or amplitude? And also, w is weight, so w = mg then?
Sorry, I'm somewhat new to physics...

Answer 3

the thing you say w is not w it's omega(angular frequency)
and a is the amplitude:)

Answer 4

Agreed

Answer 5

Thanks, guys! ^-^