Differentiate:
\[\LARGE y=\frac{e^x}{1+x}\]
What class are you in?
And for this one just use the quotient rule.
So.. \[\LARGE \frac{(1+x)(e^x)-(e^x)}{(1+x)^2}\] \[\LARGE y'=\frac{x}{(1+x)^2}\]
And I'm in calc 1.. again T_T
gg
And check your numerator.
And I never learned about e^x in calc 1 .. T_T
Yea, I'm missing an e^x.. just noticed >.<
..Which is weird..because it seems like every other school did... T_T
lol..... T_T
Can anyone here help me with advanced calc?
\[\frac{ d }{ dx }\frac{ e ^{x} }{ 1+x }=\frac{ (1+x)e ^{x}-e ^{x} }{ (1+x)^{2} }=\frac{ e ^{x}+xe ^{x}-e ^{x} }{ (1+x)^{2} }\]
and that can be reduced to \[\frac{ xe ^{^{x}} }{(1+x)^{2} }\]
So, Luigi, you're missing an e^x.
(As you yourself said.)
Anna: Please post your question in the usual way; if someone can help you, you'll likely hear from that person (or persons).
xe^x/(1+x)^2 as @mathmale answer
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