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need help on an integration problem
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\[\int\limits_{0}^{\pi/4}\tan^2xdx\]
not sure how to do this by hand
Hint: Think of an identity for (tan x)^2. Substitute for (tan x)^2.
ok thanks
sec^x-1
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thanks, got it know
Great! Now substitute (sec x)^2 - 1 for (tan x)^2. I'd strongly suggest that you enclose (sec x)^2 - 1 inside parentheses.
Good...you've been able to solve the problem on your own? Fantastic!
yes 1- (pi/4) thanks, I was not thinking about that method. Too busy thinking about u du method and using an integration formula......
sorry forgot to write (sec(x))^2 -1 typing too fast on my part
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thanks again
My great pleasure. Keep up the good work! :) MM
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