I have a question on continuous compounding. The problem asks me to calculate n for the formula A=Aok^n when A (the amount) doubles. I know I have to do logs on both sides which gives me 2=2k^n but I don't know where to go from there.

Question

amistre64 · Answer

2P = Pe^(rt)

2 = e^(rt), when rt = ln(2)

solving for t ...   t = ln(2)/r

amistre64 · Answer

i take it Ao is the 'P'rincipal amount

amistre64 · Answer

2A = Ao k^n

2A/Ao = k^n

log (2A/Ao) = n log(k)

log (2A/Ao)
---------- = n
     log(k)

amistre64 · Answer

i spose 2A is a bad thought ... let A = 2Ao,  makes more sense, so just log(2) on top