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Mathematics 13 Online
OpenStudy (anonymous):

tan(2Θ)+tan(Θ)= 0 SOLVE ON THE INTERVAL: 0≤Θ<2π

OpenStudy (mathmale):

the trick here is to find an equivalent expression in tan theta alone for tan (2 theta). Hint: look up "double angle formula." Would you be willing to look for the proper formula for tan (2*theta)?

OpenStudy (anonymous):

yeah it is: 2tanΘ/ (1-tan^2Θ)

OpenStudy (anonymous):

i made that equal to right side. then what do i do?

OpenStudy (mathmale):

Your original eqn is tan (2 theta) + tan (theta) = 0. Replace tan (2 theta) with the double angle formula that you've just typed in. Note that the resulting equation will be in tan (theta) only; your tan (2 theta) will have disappeared. Please show me (type in) what you have after this substitution.

OpenStudy (anonymous):

|dw:1393181617476:dw|

OpenStudy (mathmale):

|dw:1393181673512:dw|

OpenStudy (anonymous):

sorry thats what i meant

OpenStudy (anonymous):

so then would you make them same denominator?

OpenStudy (mathmale):

I certainly would. Would you care to try that, please?

OpenStudy (anonymous):

ok yea

OpenStudy (mathmale):

Anxious to see your result!

OpenStudy (anonymous):

|dw:1393181968828:dw|

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