tan(2Θ)+tan(Θ)= 0 SOLVE ON THE INTERVAL: 0≤Θ<2π
the trick here is to find an equivalent expression in tan theta alone for tan (2 theta). Hint: look up "double angle formula." Would you be willing to look for the proper formula for tan (2*theta)?
yeah it is: 2tanΘ/ (1-tan^2Θ)
i made that equal to right side. then what do i do?
Your original eqn is tan (2 theta) + tan (theta) = 0. Replace tan (2 theta) with the double angle formula that you've just typed in. Note that the resulting equation will be in tan (theta) only; your tan (2 theta) will have disappeared. Please show me (type in) what you have after this substitution.
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sorry thats what i meant
so then would you make them same denominator?
I certainly would. Would you care to try that, please?
ok yea
Anxious to see your result!
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