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Please help solve! 10e^(v+9)=12
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\[10e ^{v+9}=12\]
Solving for v I presume.
yes!
Divide both sides by 10 so e is isolated.
I got e^(v+9)=6/5
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is that correct?
Yep. Now take the natural logarithm of both sides. So that v+9 comes down.
would that be ln(v+9)=ln(6/5) ?
no...@ali1029 ....remeber the formula....
The right side is correct. There should be no "ln" on the left side
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so then it would just be: v+9 = ln(6/5) ?
would that be similar to v+9=6/5 or does the ln on the right side have to remain there?
What you want is |dw:1393182670667:dw|
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