medal and fan for the best answer :)

the length of a rectangle is (6x^2+3x-2)units and its width is (x^3-2x+5) units
part A: what is the area of the rectangle? show your work
part B: does the answer for part a show that polynomials are closed under and operation? justify your answer
part C: what are the degree and classification of the expression obtained in part a?

Question

medal and fan for the best answer :)

the length of a rectangle is (6x^2+3x-2)units and its width is (x^3-2x+5) units 
part A: what is the area of the rectangle? show your work
 part B: does the answer for part a show that polynomials are closed under and operation? justify your answer
part C: what are the degree and classification of the expression obtained in part a?

jiteshmeghwal9 · Answer

area of rectangle = length*breadth$$area=(6x^2+3x-2)\times(x^3-2x+5)=?$$solve it & this will be the answer for part first :)

jiteshmeghwal9 · Answer

the highest degree of the expression gt after solving will decide part third :)

anonymous · Answer

to solve the area equation do I look for like terms first?

mertsj · Answer

No.  Only if you are adding or subtracting do you look for like terms.

anonymous · Answer

so how would I begin to solve the equation @Mertsj

mertsj · Answer

Do you see this little thing: "x" between the length and width?

mertsj · Answer

(6x2+3x−2)×(x3−2x+5)=?

mertsj · Answer

Its a simple yes or no question.  Do you see it or not?

anonymous · Answer

yes I see it

mertsj · Answer

What does that little thing mean?

anonymous · Answer

multiplication

anonymous · Answer

is the answer 148?

mertsj · Answer

Do you know how to multiply polynomials?

anonymous · Answer

not really, im really bad at math

mertsj · Answer

That's why you are having trouble.

mertsj · Answer

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mertsj · Answer

Do that problem.  That might help you.

anonymous · Answer

would you multiply 2 by 2x^2+3x-4 to answer the question?

mertsj · Answer

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