Question

find the equation of the normal line to f(x)=5x^2-7 at x=-1

Answer 1

y=-2
right?

Answer 2

idk
not sure where to start

Answer 3

f(x)=5x^2-7 at x=-1
=10x-0
=10x (put the value of X here which is -1)
f`(x)=-10
find the value of y by puting x value in given equation
=5x^2-7
=5(-1)^2-7
=5-7
y=-2
Now, Use slope equation which is
y-y0=m(x-x0)
y-(-2)=-10{x-(-1)}
y+2=-10x-10
y=-10x-10-2
y=-10x-12 [This is ur normal line equation]

To check this

put the value of x in this equation
y=-10x-12
y=-10(-1)-12
y=10-12
y=-2

Answer 4

THANK YOU!!!

Answer 5

Always Welcome....