Brad tries out a weight-loss plan that involves repeatedly lifting a 48.5-kg barbell from the floor over his head to a height of 1.9 m. If he is able to complete three such lifts per minute, how long will it take for him to lose 0.50 kg of fat? "Burning" 1 g of fat supplies 39 kJ to the body; of this, 10% can be used by the muscles to lift the barbell. (Ignore the fat "burned" while he lowers the barbell to the floor.)
It doesn't say how much "effort" or energy it takes to lift the barbell.
oh wait, never mind
ok, so you've got at 48.5kg barbell. \(F=mg\) and \(W=F\Delta x\) This tells you how much energy it will take to lift the barbell. Now, it tells you "1 g of fat supplies 39 kJ to the body; of this, 10% can be used by the muscles to lift the barbell."
So when you burn 1g of fat, you're supplying 39 X10^3 J of energy to lift the barbell which requires the energy you calculated for the work. I f that makes sense.
ok, I think i get it
Cool.
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