Evaluate the integral using the properties of even and odd functions as an aid.
Well, do it. Is it even or odd? Is the range of integration symmetrical about the origin?
I'm pretty sure it's odd.
Please write the definition of an Odd Function. Pretty sure isn't good enough,
Even: f(x) = f(-x) Is that true for this function? Odd: f(x) = -f(-x) Is that true for this function?
\[\int\limits_{-2}^{2} x ^{2}(x ^{2}+1) dx\]
Help please
You haven't answer the question. Is it Odd or Even? Check out those definitions.
Oh its even
How do you know?
An even function is a function such that f(-x)=f(x). Graphically an even function is symmetrical about the y-axis while an odd function is symmetrical when rotated about the origin 180 degrees.
Am I right?
Let's see: \(f(-x) = (-x)^{2}((-x)^{2}+ 1) = x^{2}(x^{2}+1)= f(x)\) -- Perfect. Okay, how do we utilize this to simplify the integral?
hold on
do you use\[u = x ^{2}+1 \] which is du is 2x
while dx is du/2x
How does that utilize the fact that it is an Even Function? First, there is no need for a substitution. This is a simple integral. The lesson, here, is about symmetry.
Im confused?
The point you are to see is that we have this situation: 1) Even Function 2) Symmetric About the y-Axis 3) Half the integral is redundant. \(\int\limits_{-2}^{2}x^{2}(x^{2}+ 1)\;dx = 2\cdot\int\limits_{0}^{2}x^{2}(x^{2}+ 1)\;dx\)
oh yeah.. Now I got it
after this do you add 1
Sorry, mom called me
Add 1 for what? Just evaluate the integral.
okay, I'll let me work on it as soon as possible. I'm eating dinner
I had Frog Legs and Pork Chops. It was pretty good.
lol
That's cool
I don't eat meat
Also cool.
I heard people eat all sorts of thing. None of them make me scared
Well, let's eat some calculus, shall we?
lol Im almost done ... let me drink water
My frogs would like that.
I find it little hard writing the equation down
\[2 \int\limits_{0}^{2} x^{2}(x ^{2}+1)dx \]
\[x ^{2} (x ^{2}+1) \int\limits_{0}^{5}\]
Is this something like this
Remember, this is a trivial integral. If you are thinking of something fancy, you don't see it.
wouldn't you subtitute (2^2 +1) = 5 and 0^2+ 1 which the bottom is 1
instead of 0. If I'm wrong help?
Am I right?
Umm... You should first find the anti-derivative. \(\int x^{2}(x^{2} + 1)\;dx = \int x^{4} + x^{2}\;dx = ??\)
\[\frac{ x }{ 5}^{5}+ x ^{2}\]
right?
I mean x^ 3
\[\frac{ 1 }{ 5 }x ^{5}+ x ^{3}\]
Why didn't we get \(\dfrac{1}{5}x^{5} + \dfrac{1}{3}x^{3} + C\)
oh yeah plus C
I think you made a mistake its x cube
never mind sorry
What do you do after this? do you subtitute the 2 and 0 to get the answer for this question
meanwhile you subtract both of them right
First, you get the integral right. If you think there is no 1/3 in there, you should review your notes. Why did you get a 1/5 on the first piece, but nothing on the second piece? That makes no sense.
Well sorry.. wasn't paying attention.
I don't know what is wrong with me
I hope you understand me.. I make lot of mistake..
I need to get this done because I have headache.. hope you understand right
I just had seizure recently..
It is okay to make mistakes so long as you learn from them. \(2\cdot\int\limits_{0}^{2} x^{4} + x^{2}\;dx = \dfrac{1}{5}x^{5} + \dfrac{1}{3}x^{3}|_{0}^{2} = 2*(\left((1/5)32+(1/3)8\right)-\left(0\right)) = 2(35/5 + 8/3)\)
did you got 32 by 3^5
sorry 2^5
I caught up
is it 9\[9 \frac{ 2 }{ 3 }\]
?? Sorry, typo up there. 32, not 35 2(32/5 + 8/3) = 16(4/5 + 1/3) = 16(12/15 + 5/15) = 16 (17/15) It's just arithmetic.
Am I right to the final answer?
You should be able to compare my correct response with yours. You tell me if yours is correct.
it's wrong... but I should be multiplying by 2
in the end
Thanks for help!
Did you follow mine at all? The only error was that goofey 35 and the cut off of the final /3. Down below, all the arithmetic is shown. Keep trying until you get 16 (17/15) = 272/15
alright I got it I did it.
Thanks for help!
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