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Solve for x: 8^{2x+3} = 32^{x+2}
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use natural logs. drop the power and solve like a normal equation
\(\bf 8^{2x+3} = 32^{x+2}\qquad \qquad {\color{blue}{ 8\implies 2^3\qquad 32\implies 2^5}}\qquad thus \\ \quad \\ 8^{2x+3} = 32^{x+2}\implies ({\color{blue}{ 2^3}})^{2x+3}=({\color{blue}{ 2^5}})^{x+2}\) what do you think?
there you go!
Thanks drag0night
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