Mathematics
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OpenStudy (anonymous):
PROVE THE IDENTITY
cos(3t)= cost(1-4sin^2t)
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OpenStudy (anonymous):
@Mertsj
OpenStudy (anonymous):
do you start by changing left to cos(2t+t)?
OpenStudy (mertsj):
yes
OpenStudy (anonymous):
so the left side youd follow the cosine identity? and right side youd keep same?
OpenStudy (anonymous):
@Mertsj what do you do then
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OpenStudy (mertsj):
yes
OpenStudy (anonymous):
what?
OpenStudy (mertsj):
Then replace cos(2t) with 1-2sin^2t
OpenStudy (anonymous):
and then?
OpenStudy (anonymous):
sin2t with 2sintcost?
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OpenStudy (mertsj):
yes
OpenStudy (anonymous):
then?
OpenStudy (anonymous):
can someone help me with my problem
OpenStudy (mertsj):
@shubham1 Stop with the hijacking of another person's post.
OpenStudy (anonymous):
@shubham this isnt where youu ask for help. you put your question in the question box.
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OpenStudy (anonymous):
yeah, dont do that. this is my post.
OpenStudy (anonymous):
@Mertsj sorry, so you were saying?
OpenStudy (anonymous):
how do you simplify the left then
OpenStudy (mertsj):
Simplify and then factor out cos t
OpenStudy (anonymous):
so..
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OpenStudy (mary.rojas):
@shamil98 ;D
OpenStudy (mertsj):
Then you are done.
OpenStudy (mary.rojas):
She needs more guidance
OpenStudy (anonymous):
@Mertsj
Can you finish my question.
Will give medal
OpenStudy (anonymous):
please stop that.
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OpenStudy (anonymous):
if i factor out cos t can you show me cuz im a little stuck
OpenStudy (mertsj):
\[\cos (2t+t)=\cos 2t \cos t-\sin 2t \sin \sin t=(1-2\sin ^2t) \cos t-2\sin t \cos t \sin t=\]
\[\cos t-2\sin ^2t \cos t-2\sin ^2t \cos t=\cos t-4\sin ^2t \cos t=\cos t(1-4\sin ^2t)\]
OpenStudy (anonymous):
thank you!!!
OpenStudy (mertsj):
yw