the problem is let F(x) = ((x^3 - B) / (x-2)) if X

Question

the problem is
 let F(x) = ((x^3 - B) / (x-2)) if X<0  , 
 Ax+B if 0<x<4   , 0 is less than or equal to X which is less than or equal to 4
2x^2 if x>4 .
 I have to find both A ad B which make it continuous...

anonymous · Answer

If the function is continuous, then there must be a value when x = 4 & 0..  Is one supposed to be less than or equal to or greater than or equal to?  I'm assuming so.

anonymous · Answer

0 is less than or equal to X which is less than or equal to 4

nincompoop · Answer

so what the heck is the question?

anonymous · Answer

@nincompoop It's Calculus.

anonymous · Answer

Well, assuming that when x is equal to or greater than 4 the equation is 2x^2, then @ x=4 there would be the point 32

anonymous · Answer

I mean, the y-value would be 32

anonymous · Answer

This means that ax+b must also have a y-value of 32 at the x-value 4.

anonymous · Answer

at 0, the first f(x) would be b/2 and the middle f(x) would have to equal that as well.

anonymous · Answer

ok..

anonymous · Answer

Thanks