Question

the problem is
let F(x) = ((x^3 - B) / (x-2)) if X<0 ,
Ax+B if 04 . I have to find both A ad B which make it continuous...

Answer 1

If the function is continuous, then there must be a value when x = 4 & 0.. Is one supposed to be less than or equal to or greater than or equal to? I'm assuming so.

Answer 2

0 is less than or equal to X which is less than or equal to 4

Answer 3

so what the heck is the question?

Answer 4

@nincompoop It's Calculus.

Answer 5

Well, assuming that when x is equal to or greater than 4 the equation is 2x^2, then @ x=4 there would be the point 32

Answer 6

I mean, the y-value would be 32

Answer 7

This means that ax+b must also have a y-value of 32 at the x-value 4.

Answer 8

at 0, the first f(x) would be b/2 and the middle f(x) would have to equal that as well.

Answer 9

ok..

Answer 10

Thanks