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Solve for x: log3(x+4)+log3(x-2)=2
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change the equation into the exponential form, so it can be easier to solve for x
is it log base 3( x+1)or just 3*x+1
\[ \log_3(x+4)+\log_3(x-2)=2\] \[(x+4)(x-2)=2^3 \] make sense what i did here, on how i transformed the logarithm equation into the exponential form
@WAyne5
@nkaadi1995 3 is the base, i believe
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its zale 101 is correct except its 3^2 not 2^3
oh, and when u add logs together, u multiply, using the product rule
yes
Solve for x: log3(x+4)+log3(x-2)=2 becomes log3(x+4)l(x-2)=2
oh yea lol @nkaadi1995
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no as you wrote before its multiply but the mistake is in 2^3
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