Question

evaluate

Answer 1

\[\int\limits \left( \frac{ x^3-x^2 }{ x^2 } \right)dx\]

Answer 2

\[\int\limits[(x^3)(x^{-2})-(x^2)(x^{-2})]dx\]
\[\int\limits x dx -\int\limits 1dx + c\]
\[=\frac{ x^2 }{ 2 }-x+c\]

Answer 3

correct

Answer 4

@Vincent-Lyon.Fr

Answer 5

please check if my work is correct. I thought it is, but whenever I differentiate to check, it's not coming out correctly

Answer 6

\[\frac{ d }{ dx }\left( \frac{ x^2 }{ 2 }-x \right)=x-1=\left( x-1 \right)*\frac{ x^2 }{ x^ 2 } =\frac{x^3-x^2 }{ x^2 }\]

Answer 7

well if you put it that way then it would be correct. thanks
\[\int\limits \frac{ 1-x^2 }{ 1-x }dx\]

Answer 8

you are asking about another problem?
\[\int\limits \left( 1+x \right)dx=x+\frac{ x^2 }{2 }+c\]

Answer 9

\[1-x^2=(1+x)(1-x)\]