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anyone good in calculus please help and explain step by step.
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\[evaluate \lim_{x \rightarrow 2}\frac{ \int\limits_{2}^{x} \frac{ 1}{ t^3+1 } }{ x-2 }\]
use l'hopital
what is that
\[\lim_{x\to 2}\frac{f(x)}{g(x)}=\lim_{x\to 2}\frac{f'(x)}{g'(x)}\]
i dont what i did but i get zero for answer
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seems unlikely to me
so i wanted to check if that is right
take the derivative of the top take the derivative of the bottom replace \(x\) by \(2\) and you will have your answer
ok i get zero
really? what is the derivative of \[\int_2^x\frac{1}{t^3+1}dt\]?
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