Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

anyone good in calculus please help and explain step by step.

OpenStudy (anonymous):

\[evaluate \lim_{x \rightarrow 2}\frac{ \int\limits_{2}^{x} \frac{ 1}{ t^3+1 } }{ x-2 }\]

OpenStudy (anonymous):

use l'hopital

OpenStudy (anonymous):

what is that

OpenStudy (anonymous):

\[\lim_{x\to 2}\frac{f(x)}{g(x)}=\lim_{x\to 2}\frac{f'(x)}{g'(x)}\]

OpenStudy (anonymous):

i dont what i did but i get zero for answer

OpenStudy (anonymous):

seems unlikely to me

OpenStudy (anonymous):

so i wanted to check if that is right

OpenStudy (anonymous):

take the derivative of the top take the derivative of the bottom replace \(x\) by \(2\) and you will have your answer

OpenStudy (anonymous):

ok i get zero

OpenStudy (anonymous):

really? what is the derivative of \[\int_2^x\frac{1}{t^3+1}dt\]?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!