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Mathematics 7 Online
OpenStudy (anonymous):

A ball on the end of a string id spinning around a circle with a radius of 5 centimeters. If in 9 seconds a central angle of 1/3 radians has been covered, what is the angular speed of the ball?

OpenStudy (anonymous):

As the ball is going 1/27 radians /s, all we need to do is go from that to angular speed.

OpenStudy (anonymous):

The circumfrence of the circle is 10pi. Thus, the ball travels 10pi cm/2pi radians.

OpenStudy (anonymous):

Multiplying the two cancels out the radians to give us cm/s, and so the answer is 5/27 cm /s or 0.19cm/s

OpenStudy (anonymous):

can u tell me why the circumfrence is 10pi?

OpenStudy (anonymous):

Circumference is 2pir. Radius is 5 cm, therefore the circumference is 2(5)pi or 10pi.

OpenStudy (anonymous):

i still dont get it...how about this "9 seconds a central angle of 1/3 radians has been covered,"

OpenStudy (anonymous):

In 9s, the ball has travelled 1/3 radians, right? If we divide both sides by 9, then that means that the ball has travelled 1/27 radians in 1 s.

OpenStudy (anonymous):

oh ok gotcha...just let me double check this :)

OpenStudy (anonymous):

i got another :) A bicyclist average linear speed during a race was 36 mph. His bicycle wheel has a 20-in diameter. What was the angular speed of the wheel in revolutions per hour?

OpenStudy (anonymous):

Damn americans and their imperial system... lol jk one sec.

OpenStudy (anonymous):

63360 inches in a mile? What sort of messed up system is that?

OpenStudy (anonymous):

Okay fine so the bicycler traveled 2 280 960 inches per hour. The wheel rotated 20pi inches each revolution. Therefore, the number of revolutions per hour would be 2 280 960 divided by 20pi, or around 36 302.6

OpenStudy (anonymous):

Man, I am GLAD I don't live down there. One unit in Grade 9 for the Imperial System was enough for me.

OpenStudy (anonymous):

man...is this real? jk

OpenStudy (anonymous):

what do u mean down there? where do u live?

OpenStudy (anonymous):

I'm Canadian.

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

a wheel with 21 inch diameter is turning at the rate 43 revolutions per minute. To the nearest inch per minute, what is the velocity of a point on the rim?

OpenStudy (anonymous):

@greenglasses

OpenStudy (anonymous):

Bloody inches.

OpenStudy (anonymous):

It's the same basic concept as the other questions. The wheel's got a radius of 21pi right? So that means it travels 43 (21pi)/min.

OpenStudy (anonymous):

*diameter

OpenStudy (anonymous):

No wait.

OpenStudy (anonymous):

linear velocity?

OpenStudy (anonymous):

dude...we got diameter so we got radius then 43 revolutions => w= 43x2 pi

OpenStudy (anonymous):

velocity is linear speed lol

OpenStudy (anonymous):

Sorry what's w?

OpenStudy (anonymous):

angular speed

OpenStudy (anonymous):

what do u think man?

OpenStudy (anonymous):

my mind's bust I'm tired of physics. i googled it the answer is definitely c). the answer is always c). also 43 x 2 x pi is not one of the answers.

OpenStudy (anonymous):

lol the angular speed = revolutions x 2pi if u have revolutions the linear speed = r x angular speed by this i solve the second problem that i gave u, and the answer is 36302.6059 revs lol

OpenStudy (anonymous):

this is not physics man...im working on trig lol

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