Question

Help please!!!!!!!

Create your own equation written in standard form.
1. Determine any point that is a solution and will be on this line. Justify your answer algebraically.

Answer 1

@zepdrix

Answer 2

Do you remember the standard form of a line? :)

Answer 3

ax + by = c
isnt it?

Answer 4

ok good.
So just choose some numbers for a, b and c to complete the first step.

Answer 5

Or the step prior to step1 i guess :P heh

Answer 6

2x + 5y = 10

Answer 7

Ok good.
Let's come up with an ordered pair that we can use with this line.
Whatchu got? :U

Answer 8

I am confuse in this one. how do I find solution from this equation?

Answer 9

I dont know how will I able to determine any point that is a solution and will be on this line. Justify your answer algebraically.

Answer 10

Let's worry about that in a sec!! :)
First come up with a number value for x and y that we can use.

Answer 11

How about (x,y) = (3,4) ?
k? :o

Answer 12

What we want to do is,
Plug 3 in for x,
and 4 in for y,

If our equation simplfies to 10 = 10, (the equation holds true),
then (3,4) `is` a solution to the equation.

Answer 13

okay I thought I have to plug zero

Answer 14

\[\Large\bf\sf 2x + 5y = 10 \]You plug in any pair of numbers for x and y.
And then state whether or not the equation holds true for that pair.

Answer 15

okay thanks so much for help!!! :) you are too awesome!!!! thanks a lot for help!!!!!!

Answer 16

np!
understand how to finish it up? c:

Answer 17

Well pretty much I think so, lol :)

Answer 18

So is (3,4) a solution to the equation? :o

Answer 19

yes I got it

Answer 20

:)

Answer 21

^_^ you could also write it in y = mx + b and see where it crosses the line in the middle :# but that wouldn't be Ax + By = C

Just seems easier than using random values :P

Answer 22

lol :D I know but I was quite confused with solution. thanks anyways

Answer 23

thanks so much again @zepdrix !!!!!! :)

Answer 24

So the coordinate pair (3,4) is NOT a solution :o
Just making sure you understand that.

Ok ok you said you got it +_+ I'll go lol

Answer 25

actually I think I am not. I understood now how to find a solution from this kind equation :( sorry

Answer 26

how solution exactly like? if thats not solution

Answer 27

Solution is a pair of numbers that gives you 10 = 10 for this equation.

To find a solution,
Choose an easy number to work with for one of your variables,
like x=0.
\[\Large\bf\sf 2x+5y=10\]Plugging in x=0,\[\Large\bf\sf 2\cdot0+5y=10\]\[\Large\bf\sf 5y=10\]Do you understand how to solve for y from this point?

Answer 28

you mean, I have to plug zero to find solution of the equation like this one

Answer 29

zero will be `part of your solution`.

Your solution consists of 2 parts,
x=something
y=something else

Answer 30

To find one solution we're letting,
x=0
y=?

Answer 31

We have to solve the equation for y.

Answer 32

5y/5 = 10/5

y = 2

Answer 33

Ok good.
To check our work, we'll plug in x=0, y=2.\[\Large\bf\sf 2\cdot 0+5\cdot2\quad=\quad10\]\[\Large\bf\sf 10\quad=\quad 10 \qquad\color{green}{\checkmark}\]

Answer 34

So we've determined that (0,2) is a solution to the equation.

Answer 35

it is solution for just y. Right?

Answer 36

No.
it is a solution the equation.
x=0,
y=2.

Answer 37

oh yeah, I am so sorry for giving you trouble and keeping you here quite long. :( I apologize for that.

Answer 38

lol :3

Answer 39

Honestly, but thank you so much again for coming back and explaining me! :)

Answer 40

You are truly really great :) thanks for tolerating me and helping me a lot

Answer 41

and you are really cool too :) I really enjoyed learning from you

Answer 42

+_+