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Physics 19 Online
OpenStudy (anonymous):

a man pulls a 50.0 kg box with a rope parallel to the ground he pulls the box 10.0 m about how much work has he done?

OpenStudy (wolfe8):

Work is force times distance. Here, force will be the weight of the box.

OpenStudy (anonymous):

are you sure that weight can be force? and if it can can you explain?

OpenStudy (anonymous):

so would it be 500J?

OpenStudy (anonymous):

If there is no friction and no increase in elevation, there was no work.

OpenStudy (anonymous):

ok but its a question of my review and the answer choices are A.5j B.0.2J C.5,000J D.500J it doesn't 0 i think there is work

OpenStudy (wolfe8):

50 kg is the mass. Weight is mass times gravity.

OpenStudy (anonymous):

ok so is it like this? 50 x 9.8=490 490 x 10=4900 os it would be C.?

OpenStudy (wolfe8):

Yep

OpenStudy (roadjester):

yes

OpenStudy (anonymous):

thank you wolfe8

OpenStudy (roadjester):

@vjenny It's easier to send someone a message if you tag them like so @wolfe8

OpenStudy (roadjester):

=)

OpenStudy (wolfe8):

You're welcome. And btw, weight IS a force. It is the pull of gravity on mass. In science and engineering, the weight of an object is usually taken to be the force on the object due to gravity. http://en.wikipedia.org/wiki/Weight

OpenStudy (roadjester):

@wolfe8 is correct Those new to physics find this concept confusing. I myself was totally lost when I first learned it.

OpenStudy (anonymous):

thanks for the tip @roadjester and ok yeah I get it now @wolfe8

OpenStudy (anonymous):

Pulled horizontally, with no friction, the work is 0, regardless of the answers offered.

OpenStudy (roadjester):

Work is \(F\Delta x\). In order to pull the box there has to be a force on the box.

OpenStudy (anonymous):

It does not indicate any force was exerted.

OpenStudy (anonymous):

Weight comes into play when being lifted against gravity or when causing friction to oppose motion.

OpenStudy (wolfe8):

I took time to respond earlier because of this. Work is 0 when it moves perpendicular to the direction of force. Since the force is downwards and the box moves horizontally, this question maybe mistaken.

OpenStudy (anonymous):

umm ok so what do I do u mean im a bout to take this test is 10 min and the teacher told me specifically that there was going to be a question similar to this one

OpenStudy (roadjester):

You know what, let's do it this way. The "officially correct" definition of work is \(\large W=F\Delta xcos\theta\)

OpenStudy (wolfe8):

Exactly. This when theta is 90 W is 0. @vjenny I would suggest you talk to the teacher after the test if this question comes up and there were no right choices.

OpenStudy (anonymous):

It says the rope is parallel to the ground. I have been assuming the ground is horizontal.

OpenStudy (anonymous):

Good night, folks.

OpenStudy (roadjester):

Good night @douglaswinslowcooper

OpenStudy (wolfe8):

Night.

OpenStudy (anonymous):

wait so was there no work? @douglaswinslowcooper @wolfe8

OpenStudy (roadjester):

Could you type the question again with punctuation please?

OpenStudy (roadjester):

@vjenny

OpenStudy (wolfe8):

If there are no diagrams, we would have to say no since we assume the ground to logically be horizontal.

OpenStudy (anonymous):

ok let me type the question again it says A man pulls a 50.0 kg box with a rope parallel to the ground he pulls the box 10.0 M about how much is work done?

OpenStudy (roadjester):

A man pulls a 50.0 kg box with a rope parallel to the ground. This assumes the force, if any, is also parallel to the ground. He pulls the box a distance of 10.0m. So I'm going to take a shot in the dark and say theta=0. @wolfe8 why did you say it was 90?

OpenStudy (roadjester):

@vjenny I kinda meant, all punctuation. Unless the question itself was gramatically incorrect to begin with

OpenStudy (wolfe8):

Weight is downwards along the vertical axis, the movement is along the horizontal axis, so 90.

OpenStudy (roadjester):

ah

OpenStudy (roadjester):

gotcha

OpenStudy (wolfe8):

Yeah the question itself look incorrect. @.@ I kind of question your teacher haha.

OpenStudy (anonymous):

its grammatically incorrect n ok let me go take the test and I think ill choose 500 J and lets see if I get it right!

OpenStudy (roadjester):

so you're just winging it? not that good of an idea but meh. Your choice.

OpenStudy (wolfe8):

If you still have to choose I'd choose 5000 J assuming that somehow the ground is vertical.

OpenStudy (roadjester):

lol

OpenStudy (anonymous):

oops I meant 5,000 im tired I want to sleep lol ok well thanks guys

OpenStudy (wolfe8):

Maybe you should take the test during the day. Alright good luck and good night.

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