a man pulls a 50.0 kg box with a rope parallel to the ground he pulls the box 10.0 m about how much work has he done?
Work is force times distance. Here, force will be the weight of the box.
are you sure that weight can be force? and if it can can you explain?
so would it be 500J?
If there is no friction and no increase in elevation, there was no work.
ok but its a question of my review and the answer choices are A.5j B.0.2J C.5,000J D.500J it doesn't 0 i think there is work
50 kg is the mass. Weight is mass times gravity.
ok so is it like this? 50 x 9.8=490 490 x 10=4900 os it would be C.?
Yep
yes
thank you wolfe8
@vjenny It's easier to send someone a message if you tag them like so @wolfe8
=)
You're welcome. And btw, weight IS a force. It is the pull of gravity on mass. In science and engineering, the weight of an object is usually taken to be the force on the object due to gravity. http://en.wikipedia.org/wiki/Weight
@wolfe8 is correct Those new to physics find this concept confusing. I myself was totally lost when I first learned it.
thanks for the tip @roadjester and ok yeah I get it now @wolfe8
Pulled horizontally, with no friction, the work is 0, regardless of the answers offered.
Work is \(F\Delta x\). In order to pull the box there has to be a force on the box.
It does not indicate any force was exerted.
Weight comes into play when being lifted against gravity or when causing friction to oppose motion.
I took time to respond earlier because of this. Work is 0 when it moves perpendicular to the direction of force. Since the force is downwards and the box moves horizontally, this question maybe mistaken.
umm ok so what do I do u mean im a bout to take this test is 10 min and the teacher told me specifically that there was going to be a question similar to this one
You know what, let's do it this way. The "officially correct" definition of work is \(\large W=F\Delta xcos\theta\)
Exactly. This when theta is 90 W is 0. @vjenny I would suggest you talk to the teacher after the test if this question comes up and there were no right choices.
It says the rope is parallel to the ground. I have been assuming the ground is horizontal.
Good night, folks.
Good night @douglaswinslowcooper
Night.
wait so was there no work? @douglaswinslowcooper @wolfe8
Could you type the question again with punctuation please?
@vjenny
If there are no diagrams, we would have to say no since we assume the ground to logically be horizontal.
ok let me type the question again it says A man pulls a 50.0 kg box with a rope parallel to the ground he pulls the box 10.0 M about how much is work done?
A man pulls a 50.0 kg box with a rope parallel to the ground. This assumes the force, if any, is also parallel to the ground. He pulls the box a distance of 10.0m. So I'm going to take a shot in the dark and say theta=0. @wolfe8 why did you say it was 90?
@vjenny I kinda meant, all punctuation. Unless the question itself was gramatically incorrect to begin with
Weight is downwards along the vertical axis, the movement is along the horizontal axis, so 90.
ah
gotcha
Yeah the question itself look incorrect. @.@ I kind of question your teacher haha.
its grammatically incorrect n ok let me go take the test and I think ill choose 500 J and lets see if I get it right!
so you're just winging it? not that good of an idea but meh. Your choice.
If you still have to choose I'd choose 5000 J assuming that somehow the ground is vertical.
lol
oops I meant 5,000 im tired I want to sleep lol ok well thanks guys
Maybe you should take the test during the day. Alright good luck and good night.
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