Question

I need some help with IUPAC naming for the following questions (not decided, just if I need help)
2-3 questions should give me the idea of it.
Any help is highly appreciated :)

Answer 1

What's the question(s)?

Answer 2

[Co(NH3)5 Cl]Cl2

Answer 3

This question please :3 !!

Answer 4

So, you have, just to be clear, \(\sf \color{red}{[Co(NH_3)_5Cl]~Cl_2}\) ?

Answer 5

The rules state that the central metal atom takes on the end name. Additionally, you name them in alphabetical order, along with the appropriate number prefix.

For the given example, you have: 5 ammonia, and 1 chorine, so you have pentaamminechlorocobalt (III) chloride
(I think you can also use Pentaamminemonochlorocobalt(III) chloride) mono meaning 1.
The roman numeral III indicates the oxidation state of the central metal atom. and the chloride is simply the Cl\(_2\) on the OUTSIDE of the brackets.

Answer 6

@abb0t I have a doubt though, I am obviously going wrong with one of my facts but anyway, here's why I am not getting the same 'OXIDATION NUMBER'

Answer 7

Cl has -1 charge, NH3 is neutral ... right?

Answer 8

Yes, NH\(_3\) is neutral.

Answer 9

So if i represent oxidation number of Cobalt as x then :
x-1=-2 ?

Answer 10

that doesn't give 3 ... Please tell me the error of my ways.

Answer 11

Shouldn't you have = +2?

Answer 12

how :O ?

Answer 13

I thought that Cl had a negative charge? That makes it = -2 right?

Answer 14

Charge of complex ion - total carge of all ligands
so, 2+-[5\(\times\)0+(-1)] = 3+

Answer 15

I still don't understand the representation. you are saying that
x+(5*0)-1=2 ?

Answer 16

Cl2 is the anion right? So how come it got the positive charge?

Answer 17

@abb0t

Answer 18

It actually carries a 2 charge since you have two chlorines = -2
hence, to make it neutral, the two Cl\(_2\).

Answer 19

so you are saying that we take it to be +2 instead of -2 because we need to make it neutral ?

Answer 20

yes.

Answer 21

Oh i finally get it!!!!

Answer 22

[Co(NH3)5 Cl]Cl2 was my original question
since Cl has -1 charge the stuff inside the bracket has to be equal to +2 to make their sum 0

Answer 23

so we equate x-1=+2
my explanation wasn't proper but I got your point. Thanks a tonne ^_^ @abb0t

Answer 24

yes.

Answer 25

the counter ion, in this is Cl\(_2\) is there to keep it electrically neutral.

Answer 26

NO3 is neutral or ... ? whats the charge?

Answer 27

1-

Answer 28

What would be the charge for :
\[ZnCl _{4}\]

Answer 29

The charge or oxidation state?

Answer 30

I was asking for the over all charge. Any way, I learnt quite a long these days. Thanks for your concern :) @abb0t