Question

A block of mass 3 kg slides down an inclined plane inclined at 30° with respect to horizontal. The frictional force between the block and the plane is 8.7 N and the length of the plane is 1 m. What is the work done by the net force when the block reaches the bottom of the plane? and why?

Answer 1

find the net force first

Answer 2

is the answer 6j @random231

Answer 3

howd u get it?

Answer 4

the net force is the force of gravity minus the force of friction
Fnet = Fgravity - Friction
Fnet = m*g*sin30 - 8.7
we use m*g*sin30 because only a component of the force of gravity is causing the block to slide down the incline.
so Fnet = 6

Work = Fx where F is the net force and x is the distance
W = 6 * 1

W = 6J

Answer 5

yah well actually 6.3
ok

Answer 6

u r right

Answer 7

how did you do it?

Answer 8

same way theres no other alternative

Answer 9

thanks!