Question

regr

Answer 1

@quinnisaghost

Answer 2

@jdoe0001

Answer 3

cos^2(x) = [1 + cos(2x)]:
(3/2)cos^2(2x) - 3cos(2x) + 3/2
= (3/4)[1 + cos(4x)] - 3cos(2x) + 3/2
= 3/4 + (3/4)cos(4x) - 3cos(2x) + 3/2
= 9/4 - 3cos(2x) + (3/4)cos(4x).
i'm bad at trig idk ugh. lol

Answer 4

@quinnisaghost how did you get the first step?

Answer 5

Megatron!

Answer 6

yuuppp can you help me?

Answer 7

@sourwing

Answer 8

@lalaly @Zarkon @jdoe0001

Answer 9

@whpalmer4 @wolfe8

Answer 10

@agent0smith @shamil98 @Destinymasha

Answer 11

That first step looks like an identity to me.

Answer 12

no how did quinnisaghost get from sin^6(theta/4) to (3/2)cos^2(2x) - 3cos(2x) + 3/2

Answer 13

Check out power-reducing http://www.sosmath.com/trig/Trig5/trig5/trig5.html I'm not sure unless I try it myself and right now going for dinner.

The name goes with what the question wants too.

Answer 14

ok thanks