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OpenStudy (loser66):
My logic is \(\dfrac{P_AV_A}{T_A}= \dfrac{P_FV_F}{T_F}\) replace numbers in, I have \(T_F = 1.56T_A\) Which means temperature increases.
The process is adiabatic one which shows Q = 0, and \(\triangle U= W \) . W >0 \(\rightarrow \triangle U >0\) means U increases. Should I check the first option, too? Not sure.
OpenStudy (isaiah.feynman):
What's U?
OpenStudy (isaiah.feynman):
Yes check the first option.
OpenStudy (loser66):
what's else?
OpenStudy (isaiah.feynman):
Nothing more! q cannot provide energy since its zero, it also cannot be greater than W since its zero still!
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OpenStudy (loser66):
why do you think Q =0?
OpenStudy (isaiah.feynman):
The process is adiabatic.
OpenStudy (loser66):
The problem said that it is NOT a diabatic,
OpenStudy (loser66):
oh, my bad. I am sorry, still have another guide, let me post it
OpenStudy (isaiah.feynman):
No wait did the question say its adiabatic?
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OpenStudy (isaiah.feynman):
So what's the question?
OpenStudy (loser66):
OpenStudy (loser66):
:) I am sorry, I am so tired now. :)
OpenStudy (isaiah.feynman):
I'd say second one.
OpenStudy (loser66):
me too. I got the second one, consider the first one, (I have a proof of it, too)
Think of the third one, since the volume changes --> work done on gas