Question

HELP MEDAL FOR ANSWER!!!!!!!!!!!!!!!!!!!!!!


Which inequality models this problem?

The length of a rectangle is four times its width. If the perimeter is at most 130 centimeters, what is the greatest possible value for the width?

A.
2w + 2 • (4w) < 130

B.
2w + 2 • (4w) > 130

C.
2w + 2 • (4w) ≤ 130

D.
2w + 2 • (4w) ≥ 130

Answer 1

PLEASE HELP!

Answer 2

Well we know that the perimeter is two lengths and two widths:

Answer 3

If the maximum is 130, then that means:
\[2(length) + 2(width)\le130\]

Answer 4

Can you go from here?

Answer 5

NOT REALLY IM BAD AT MATH

Answer 6

SOMEONE ELSE PLEASE HELP

Answer 7

length = 4w
width = w

Plug those into the above equation..

Answer 8

\(\bf length =l\qquad width=w
\\ \quad \\

\textit{The length of a rectangle}\implies l\\
\textit{is four times its width.}\implies =4\times w\implies {\color{blue}{ 4w}}
\\ \quad \\

\textit{perimeter of a rectangle }=l+w+l+w\implies 2l+2w
\\ \quad \\
\textit{perimeter is at most 130 centimeters}\implies perimeter = p \le 130\ cm\\

------------------------------\\
p=2l+2w\implies p \le 130\ cm\implies 2l+2w \le 130
\\ \quad \\
2({\color{blue}{ 4w}})+2w \le 130\)

Answer 9

something is AT MOST
meaning, it can be THAT MUCH or less, but not above that, thus LESS THAN OR EQUALS TO or \(\large \le\)