Question

PLEASE HELP
Check my answer?

Answer 1

got picture?

Answer 2

nope there's no picture

Answer 3

@Mertsj can you please help me?

Answer 4

I think that is right...assuming that the 24 is 2p, or is it 4p? I forget. I'd better look it up.

Answer 5

more or less

Answer 6

the mic is 24 inches wide, thus 12 units on one side and 12 units on the other

Answer 7

so its either 4 or 12?

Answer 8

then you'd just need to get the equation of that parabola, to get the distance from the focus to the vertex
since the mic itself is at the focus of the dish

Answer 9

recall that \(\large \bf (x-h)^2=4p(y-k)\)

p = distance from the vertex to the focus

Answer 10

so you're really being asked for "p"

Answer 11

h,k is 12, 4 or 24, 4 ?

Answer 12

(h, k) is the vertex of the parabola, notice the parabola is at the origin

Answer 13

so we know the vertex, thus (h, k)
then we'd need another point in the parabola, notice the picture, you'd have two you can use

so let's say let use use the (-12, 4) so \(\bf (x-h)^2=4p(y-k)\implies (x-0)^2=4p(y-0)\implies x^2=4py
\\ \quad \\
{\color{blue}{ (-12, 4)}}\implies {\color{blue}{ -12}}^2=4p{\color{blue}{ 4}}\)

solve for "p"

Answer 14

well, I should enclose the "x" , so \(\bf (x-h)^2=4p(y-k)\implies (x-0)^2=4p(y-0)\implies x^2=4py
\\ \quad \\
{\color{blue}{ (-12, 4)}}\implies ({\color{blue}{ -12}})^2=4p{\color{blue}{ 4}}\)

Answer 15

so p = 4 c; ; the vertix should be placed 4 inches far

Answer 16

Can you please help me with 2 more?

Answer 17

hmmm p = 4?

Answer 18

its not correct?

Answer 19

weird it doesn't show your viewing this, I keep thinking youve left

Answer 20

\(\bf {\color{blue}{ (-12, 4)}}\implies ({\color{blue}{ -12}})^2=4p{\color{blue}{ 4}}\implies \cfrac{144}{4\cdot 4}=p\)

Answer 21

wait 9 ? what

Answer 22

yes

Answer 23

I think I did some wrong at first but thank you so much(:

Answer 24

as far as the other... repost anew, thus more exposure and we can revise each other

Answer 25

Okay (: