evaluate the Acrsin(1)?
se sine is -1". --- Then you have to know that sine is -1 when the angle is 270 degrees or (3/2)pi radians. ---- If you know both of those things, you know the answer to your problem is arcsin(-1) = 270 degrees. http://answers.yahoo.com/question/index?qid=20100607122350AAjs51L
but its the arcsin(1) not -1?
@KinzaN
\[\sin^{-1} (1)\] is what you're looking for--
it's 90 degrees or pi/2 radians.
yes but i am suppose to solve it using special right triangles?
or unit circles
Ah, I always think graphically. You'd use unit circle, though, I suppose.
it would be the point (0,1) which is on the y axis at 90 degrees?
On the unit circle, sin(1) is on the "point" (1, 0) where the angle is 0 or 2pi. The inverse would be (0, 1) where the angle is pi/2 or 90 degrees.
Right. =D
ok and one more?
:D
What?
arctan(radical 3 over 3)
|dw:1393287050482:dw| would it be 60?
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