Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

evaluate the Acrsin(1)?

OpenStudy (anonymous):

se sine is -1". --- Then you have to know that sine is -1 when the angle is 270 degrees or (3/2)pi radians. ---- If you know both of those things, you know the answer to your problem is arcsin(-1) = 270 degrees. http://answers.yahoo.com/question/index?qid=20100607122350AAjs51L

OpenStudy (anonymous):

but its the arcsin(1) not -1?

OpenStudy (anonymous):

@KinzaN

OpenStudy (anonymous):

\[\sin^{-1} (1)\] is what you're looking for--

OpenStudy (anonymous):

it's 90 degrees or pi/2 radians.

OpenStudy (anonymous):

yes but i am suppose to solve it using special right triangles?

OpenStudy (anonymous):

or unit circles

OpenStudy (anonymous):

Ah, I always think graphically. You'd use unit circle, though, I suppose.

OpenStudy (anonymous):

it would be the point (0,1) which is on the y axis at 90 degrees?

OpenStudy (anonymous):

On the unit circle, sin(1) is on the "point" (1, 0) where the angle is 0 or 2pi. The inverse would be (0, 1) where the angle is pi/2 or 90 degrees.

OpenStudy (anonymous):

Right. =D

OpenStudy (anonymous):

ok and one more?

OpenStudy (anonymous):

:D

OpenStudy (anonymous):

What?

OpenStudy (anonymous):

arctan(radical 3 over 3)

OpenStudy (anonymous):

|dw:1393287050482:dw| would it be 60?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!