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Chemistry 16 Online
OpenStudy (anonymous):

How can I calculate the atomic mass of chlorine-35 Mass(amu) 34.969 Abundance(%) 75.78

OpenStudy (aaronq):

you need the atomic mass of Cl-35? it's given in the question

OpenStudy (anonymous):

isnt it 35?

OpenStudy (aaronq):

its 34.969 amu. It seems like you're missing info though, the question doesn't seem complete.

OpenStudy (anonymous):

im going to attach a file

OpenStudy (anonymous):

OpenStudy (aaronq):

sorry, i don't open files unless they're pdfs. It's a security thing.

OpenStudy (anonymous):

i understand let me write the question

OpenStudy (anonymous):

Given the information below calculate the atomic mass of chlorine. Isotope Chlorine-35 Mass(amu) 34.969 Abundance(%) 75.78

OpenStudy (aaronq):

i think that they want the \(average\) atomic mass of chlorine. Do you have the mass of the other isotope(s)? you would apply \(average=\Sigma(mass_i*Abundance_i)\)

OpenStudy (anonymous):

yes its chlorine again Chlorine -37 Mass (amu) 36.966 ABUNDANCE (%) 24.22

OpenStudy (aaronq):

okay, so do you know how to apply the formula i posted? \(\Sigma\) just means sum, btw.

OpenStudy (anonymous):

it would be 34.969*75.78

OpenStudy (aaronq):

you need to use both of the isotopes, remember this is the average (technically the weighted average). You also have to convert the percents given, 75.78%=0.7578 (divide by 100).

OpenStudy (anonymous):

so 34.969*.7578 and 36.966*.2422. From there am I ok with the two answers?

OpenStudy (aaronq):

thats good. now you just need to add them up average atomic mass = (34.969*.7578) + (36.966*.2422)

OpenStudy (anonymous):

i get it thank you

OpenStudy (aaronq):

cool cool, no problem.

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