How can I calculate the atomic mass of chlorine-35 Mass(amu) 34.969 Abundance(%) 75.78
you need the atomic mass of Cl-35? it's given in the question
isnt it 35?
its 34.969 amu. It seems like you're missing info though, the question doesn't seem complete.
im going to attach a file
sorry, i don't open files unless they're pdfs. It's a security thing.
i understand let me write the question
Given the information below calculate the atomic mass of chlorine. Isotope Chlorine-35 Mass(amu) 34.969 Abundance(%) 75.78
i think that they want the \(average\) atomic mass of chlorine. Do you have the mass of the other isotope(s)? you would apply \(average=\Sigma(mass_i*Abundance_i)\)
yes its chlorine again Chlorine -37 Mass (amu) 36.966 ABUNDANCE (%) 24.22
okay, so do you know how to apply the formula i posted? \(\Sigma\) just means sum, btw.
it would be 34.969*75.78
you need to use both of the isotopes, remember this is the average (technically the weighted average). You also have to convert the percents given, 75.78%=0.7578 (divide by 100).
so 34.969*.7578 and 36.966*.2422. From there am I ok with the two answers?
thats good. now you just need to add them up average atomic mass = (34.969*.7578) + (36.966*.2422)
i get it thank you
cool cool, no problem.
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