Question

Line AB contains points A (−3, 5) and B (−3, 3). Line AB has a slope that is

zero

undefined

positive

negative

Answer 1

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ -3}}\quad ,&{\color{blue}{ 5}})\quad &({\color{red}{ -3}}\quad ,&{\color{blue}{ 3}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\)

Answer 2

If your line is parallel to the x-axis, the slope is 0 — it neither rises nor falls.

If your line is parallel to the y-axis, the slope is undefined and the equation is not a function because there is not a unique value of \(y\) for every unique value of \(x\).

If your line goes up as you move to the right, the slope is positive.

If your line goes down as you move to the right, the slope is negative.

Each movement of 1 unit to the right adjusts the value of \(y\) by adding \(1*m\) to the previous value of \(y\). A slope of 1 means that for each unit you move right, you also move up 1 unit.