write the equation of the line parallel to y=-3, passing through the point (2,5)

Question

anonymous · Answer

y=(0/1)2+5

anonymous · Answer

leme check...im not sure

anonymous · Answer

how did you get that?

anonymous · Answer

well, since the first line is just y = 3...that means the line is going horizontal so excuse me its (1,0)

anonymous · Answer

m is the slope...equation is y+mx+b

anonymous · Answer

*y=mx+b

anonymous · Answer

this doesnt have a slope just the y intercept. So what would be the final answer im confused

anonymous · Answer

5=(1/0)2+b

anonymous · Answer

...wait a sec... leme check my books

anonymous · Answer

its been years since i have done this

anonymous · Answer

alright :)

anonymous · Answer

this will take 5 minutes at the most

anonymous · Answer

thats fine

whpalmer4 · Answer

$$y = -3 $$is a horizontal line.  It therefore has $m = 0$
$$y = mx + b$$$$y = mx - 3$$$$y = 0x-3$$$$y = -3$$

anonymous · Answer

...he will answer it...its 10 oclock where i am an i am tierd...sorry i held u up

whpalmer4 · Answer

To fit a line through the desired point with the desired slope, use the point-slope formula:
$$y-y_0 = m(x-x_0)$$

Your target point is $(x_0,y_0)$, and your slope is $m = 0$

anonymous · Answer

oh I see Thanks to both of you! :)

whpalmer4 · Answer

The final result here is rather trivial, of course:

$$y - 5 = 0(x-2)$$$$y -5 = 0$$$$y = 5$$