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Geometry 14 Online
OpenStudy (anonymous):

help meee >>>> give two examples that support the conjecture, and one counterexample that shows the conjecture is false.

OpenStudy (anonymous):

for any real number n, \[\sqrt{n}2 = n\]

OpenStudy (anonymous):

thats n squared, btw

OpenStudy (anonymous):

Umm well n squared under a radical is actually just n when simplified So n=n. That's one thing that supports it right?

OpenStudy (anonymous):

uh huh.

OpenStudy (anonymous):

That's all I can see from what I know. I wish I could help more though

OpenStudy (anonymous):

I'm not sure if substitution may have anything to do with it.

OpenStudy (anonymous):

thats okay. thank you.

OpenStudy (anonymous):

maybe a counterexample can be like if \[\sqrt{n} = n\]

OpenStudy (anonymous):

but they won't be = if you actually put a number in there.

OpenStudy (anonymous):

ohh. ok i see.

OpenStudy (anonymous):

You understand ? :D

OpenStudy (anonymous):

not really, lol

OpenStudy (anonymous):

Lol. I'm sorry ._. I tried

OpenStudy (anonymous):

dont worry, you did perfectly fine. thanks.

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