Question

f(x) = ln(49 sin^2 x)
f'(x) = ?
Would it be
(1/49 sin^2x) * (49)(2sinx)(cosx)

Answer 1

Looks about right to me.

Answer 2

can i get rid of 49's
2sinxcosx/sin^2x

Answer 3

Yes, you can.

Answer 4

thanks

Answer 5

Let's see:

After you cancelled the 49, it turns into 2(sin x)(cos x) / (sin x)(sin x), right?

Answer 6

What else can you cancel?

Answer 7

Well, guess I won't ask the obvious and give it to you straight out.

2(cos x)/(sin x)
= 2(cot x)

(Look at the trigonometry identities!)

Answer 8

Good point. I didn't think to go further with it.

Answer 9

Thanks for the help!