Question

Solving Rational Equations:

1/v^2= 1- 2v^2 + 2v -144/v^2


Please help! Confused, please show work

Answer 1

Get the constants on one side and the terms with variables in them on the other, then combine the like terms.
Could you attempt this?

Answer 2

So, multiple by v^2

Answer 3

but then I'm faced with v^2 times 2v... how does that work?

Answer 4

does it reduce to 1= v^2 -2v- 142?

Answer 5

1/v^2= 1- 2v^2 + 2v -144/v^2
1/v^2 + 2v^2 - 2v + 144/v^2 = 1
145/v^2 + 2v^2 - 2v = 1
145 + 2v^4 - 2v^3 = 1
2v^4 - 2v^3 + 144 = 0

Answer 6

Do I solve as a

Answer 7

quadratic?

Answer 8

Cause I need to find "V"

Answer 9

v^4 - v^3 + 72 = 0
Now, factor it out. and then solve for v.
You will get complex solutions.

Answer 10

I don't think that right how Im doing it, cause my class does this. I'll attach my work for another problem

Answer 11

\[\frac{ 6 }{ b ^{2} } + \frac{ 6b-48 }{ 7b ^{2} }=\frac{ 1 }{ 7b ^{2} }\]

Answer 12

So then I multiplied both sides by 7b^2

Answer 13

and it reduced to "6/7+6b-48=1"

Answer 14

then I solved algebraically to get 8 and 3/6

Answer 15

@shamil98 help please

Answer 16

6/b^2 + 6b -48/7b^2 = 1/7b^2
42/b^2 + 6b - 48/7b^2 = 1/7b^2
6(b-1)/7b^2 = 1/7b^2

Answer 17

42/7b^2*