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Geometry 14 Online
OpenStudy (anonymous):

give a counterexample of the following conjecture. if a,b,c, and, d are real numbers such that a>b and c>d , then ac > bd.

OpenStudy (anonymous):

Let a=-2 and b=-1 such that -2<-1 Let c=-1 and d=4 such that -1<10 Then (-2)(-1)>(-1)(4)

OpenStudy (anonymous):

Kinda confusing but just go over the numbers

OpenStudy (anonymous):

@rxinstorm Do you follow?

OpenStudy (anonymous):

not really...i suck at math, sorry.

OpenStudy (anonymous):

Ok do you follow the statement if a,b,c, and, d are real numbers such that a>b and c>d , then ac > bd.

OpenStudy (anonymous):

where did you get those numbers from though? blacklabel

OpenStudy (anonymous):

^

OpenStudy (anonymous):

Guys dont show your ignorance -.- Counter examples are examples that show that a statement is false. You can pull any number out of the bag as long as you show that its not true

OpenStudy (anonymous):

I'm just wondering, maybe that's what she needs to learn?

OpenStudy (anonymous):

She needs to learn what the original statement means. if a,b,c, and, d are real numbers such that a>b and c>d , then ac > bd This means lets say there are 4 different number a,b,c and d and numbers a and c are smaller than numbers b and d thennn they are assuming that when you multiply the 2 smaller number it will be a smaller number than when you multiply the 2 bigger numbers

OpenStudy (anonymous):

umm what grade are you in?

OpenStudy (anonymous):

me? 10th.

OpenStudy (anonymous):

ohhhhh weird that u gotta do this kind of math

OpenStudy (anonymous):

why do you say that

OpenStudy (anonymous):

this isnt smth I covered in HS I think its doable but I just feel that you are lacking basic knowledge to even solve this problem

OpenStudy (anonymous):

im in geometry. its actually in a review packet that im doing. i have midterms tomorrow......

OpenStudy (anonymous):

I can attempt to explain but Its not something you learn on one foot

OpenStudy (anonymous):

Umm you understand that a,b,c and d are variables that can assume any value right

OpenStudy (anonymous):

true. but it actually kind of made sense to me, when you were explaining it earlier.

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Ok a conjecture is a statement that has been made after much thought but not neccesarily is it true

OpenStudy (anonymous):

For example I think that your hair is black . Its a statement that I have made but its not necessarily true

OpenStudy (anonymous):

oohhh

OpenStudy (anonymous):

A counter example is taking an example and showing that whtvr i said isnt true SO for example you would get on cam and show that your hair is blonde. Basically you can take any example and show how the statement isnt true

OpenStudy (anonymous):

alright, i got it. but like, how do i write down the answer for this question?

OpenStudy (anonymous):

So basically the conjecture or the statement that was proposed is if a,b,c, and, d are real numbers such that a>b and c>d , then ac > bd

OpenStudy (anonymous):

We have to show that this aint true

OpenStudy (anonymous):

Ok so you give me examples of a, b c and d and make sure that a equals less than b and that c equals less than d

OpenStudy (anonymous):

should i use numbers?

OpenStudy (anonymous):

and then we will multiply the 2 smaller numbers and the 2 bigger numbers and see if a*c<b*d

OpenStudy (anonymous):

Yess of course. These dummy variables just mean that you can choose any number that fits the conditions

OpenStudy (anonymous):

lol ok

OpenStudy (anonymous):

-1 < 2 and 1 < 3 a= -1, b=2, c=1, d= 3. therefore ac < bd

OpenStudy (anonymous):

is that right....?

OpenStudy (anonymous):

Ok good that shows you that the statement is correct. Now we want to find numbers that shows that the statement IS NOT correct

OpenStudy (anonymous):

Which should be just one number that throws it off right?

OpenStudy (anonymous):

wait. didnt i just do the one that shows that the statement is not correct?

OpenStudy (anonymous):

i just changed the signs. like put < instead of >

OpenStudy (anonymous):

._.

OpenStudy (anonymous):

Okkkk lets rewrite the question

OpenStudy (anonymous):

lol sorry...

OpenStudy (anonymous):

fineee sooooo Let a>b and c>d Your answer will still be the same Just switch around your variables

OpenStudy (anonymous):

We Just screwed up the variables.... Use your example and just tweak it

OpenStudy (anonymous):

a= 2, b= -1, c=3, d= 1. <--- changed it. now, 2> -1 and 3> 1 meaning, a> b and c> d the statement is true.

OpenStudy (anonymous):

YAAAA :D

OpenStudy (anonymous):

yayayay

OpenStudy (anonymous):

Okkk now lets find example where the statement isnt true. This is called a counterexample

OpenStudy (anonymous):

Its kinda trickyy Keep in mind that multiplying 2 negative variables will give you a positive value and multiplying a negative with a positive will give you a negative value You can look at my example that I gave originally. Just remember to switch the variables cuz i screwed up

OpenStudy (anonymous):

ok but do i use the same numbers and variables and just change the sign? change ">" to "<" sorry, my laptop died...

OpenStudy (anonymous):

Hmmm try it out on your own Just make sure that a>b and that c>d

OpenStudy (anonymous):

ummm and know that -1>-2

OpenStudy (anonymous):

ohh ok. 2>3 and 4>5 a=2, b=3, c=4, and d=5

OpenStudy (anonymous):

@BlackLabel

OpenStudy (anonymous):

Sorry I had to go out for a few minutes

OpenStudy (anonymous):

ummm how is 2>3 That cant be???? 3>2

OpenStudy (anonymous):

2 can NOT be greater than 3

OpenStudy (anonymous):

Th original conditions a>b and c>d must be true BUTTTT ac>bd should be false meaning We want to find numbers such that a>b and c>d and ac<bd

OpenStudy (anonymous):

wait wait

OpenStudy (anonymous):

ok but i made a completely false statement on purpose bc we're proving it to be false.

OpenStudy (anonymous):

Nope i forgot that you never took a logic course and that you are only in grade 10 -.- But we want to find values such that the first part is true a>b and c>d BUTTT ac<bd We only want the second part to be false

OpenStudy (anonymous):

Lemme give you a concrete example

OpenStudy (anonymous):

If it is raining then it is warm outside If this statement is false then We need to find a time that it is raining BUT it is cold outside

OpenStudy (anonymous):

sigh.

OpenStudy (anonymous):

So the first part always stays trueee But the second half is false

OpenStudy (anonymous):

See you are missing the basics in order to solve this and thats why I was surprised you were in grade wo

OpenStudy (anonymous):

10*

OpenStudy (anonymous):

ok so like, 2>1 and 3>5?

OpenStudy (anonymous):

Ill give you the answer and you try to understand it ok?

OpenStudy (anonymous):

alright.

OpenStudy (anonymous):

maybe that will be easier

OpenStudy (anonymous):

Ok let a=-2 and b=-3 sooo -2>-3 Let c=1and d=-1 such that 1>-1 Nowwww ac<bd ----> (-2)(1)<(-3)(-1) ------> -2<3

OpenStudy (anonymous):

oh. isnt that what i did earlier?

OpenStudy (anonymous):

Ummm Nooo you didnt include the negatives

jigglypuff314 (jigglypuff314):

counterexample is an example that disproves an example. doesn't matter what numbers you use. therefore BlackLabel was right about the loophole in your problem about the negatives... problem said to give counterexample, BlackLabel gave it. Done.

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