Normal line problem:
Hello.
First, do you know how to find the equation of a normal line from a point if the function is given?
Find the derivative, plug in x to get the slope and then use that and the given points to find the new equation?
Almost correct.
Do you know that normal line is perpendicular to the tangent line?
Oh, right, negative reciprocal slope.
Yep.
So after we do that how do we know where they intersect? Draw a graph?
First, did you find the equation of the normal line at (5,0) of the function y=25x-5x^2?
Uhm.. \[\ y=25x-5x^2\] \[\ y'=25-10x~~at~x=5\] \[\ y'=25-50=-25\] \[\LARGE y-0=\frac{1}{25}(x-5)\] \[\LARGE y=\frac{1}{25}x-\frac{1}{5}\]
Good!. Now, let's simplify the problem a bit. Can you put the equation of the normal line in form of x=ay+b?
Hmm.. \[\LARGE x=-25y+5\]
*25y
Yes. Now, you have to find the intersection between that and y=25x-5x^2. You can just substitute.
That'll be fun, I think I got it from here, thanks for the help :)
Yep. :)
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