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Mathematics 22 Online
OpenStudy (*insert name here*):

Normal line problem:

OpenStudy (*insert name here*):

http://prntscr.com/2vmoh1

OpenStudy (science0229):

Hello.

OpenStudy (science0229):

First, do you know how to find the equation of a normal line from a point if the function is given?

OpenStudy (*insert name here*):

Find the derivative, plug in x to get the slope and then use that and the given points to find the new equation?

OpenStudy (science0229):

Almost correct.

OpenStudy (science0229):

Do you know that normal line is perpendicular to the tangent line?

OpenStudy (*insert name here*):

Oh, right, negative reciprocal slope.

OpenStudy (science0229):

Yep.

OpenStudy (*insert name here*):

So after we do that how do we know where they intersect? Draw a graph?

OpenStudy (science0229):

First, did you find the equation of the normal line at (5,0) of the function y=25x-5x^2?

OpenStudy (*insert name here*):

Uhm.. \[\ y=25x-5x^2\] \[\ y'=25-10x~~at~x=5\] \[\ y'=25-50=-25\] \[\LARGE y-0=\frac{1}{25}(x-5)\] \[\LARGE y=\frac{1}{25}x-\frac{1}{5}\]

OpenStudy (science0229):

Good!. Now, let's simplify the problem a bit. Can you put the equation of the normal line in form of x=ay+b?

OpenStudy (*insert name here*):

Hmm.. \[\LARGE x=-25y+5\]

OpenStudy (*insert name here*):

*25y

OpenStudy (science0229):

Yes. Now, you have to find the intersection between that and y=25x-5x^2. You can just substitute.

OpenStudy (*insert name here*):

That'll be fun, I think I got it from here, thanks for the help :)

OpenStudy (science0229):

Yep. :)

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