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According to the following reaction, how many moles of carbon dioxide will be formed upon the complete reaction of 22.8 grams of butane (C4H10) with excess oxygen gas? butane (C4H10) (g) + oxygen (g) carbon dioxide (g) + water (g
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Need to start with balanced reaction equation, same number of C,H,O atoms on both sides of reactants = products equation. Then determine how many moles of butane you are starting with from its molecular weight and the mass, 22.8 g. All its carbon will become CO2.
\[2C _{4}H _{10}+13O _{2}=8CO _{2}+10H _{2}O\]
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