Question

how do you get the radius of 5 with the points (1/rad.5, -2/rad5)

Answer 1

\(\left(\dfrac{1}{\sqrt{5}}\right)^{2} + \left(\dfrac{-2}{\sqrt{5}}\right)^{2} = \dfrac{1}{5} + \dfrac{4}{5} = 1\)

Answer to your question is, "you don't". Why told you that you could?

Answer 2

the question is in standard position and the terminal side of theta intersects the unit circle at the point (1/rad5,-2/rad5) find sin cos and tan

Answer 3

What Quadrant is it in?

Answer 4

it doesn't say

Answer 5

Yes it does. Where does it intersect the unit circle? That tells you.

Answer 6

its in standard position and it only gives you the points i listed above

Answer 7

And that tells you the quadrant. Come on. You have to get this piece.

x > 0 and y < 0. What Quadrant is it in?