how do you get the radius of 5 with the points (1/rad.5, -2/rad5)

Question

tkhunny · Answer

$\left(\dfrac{1}{\sqrt{5}}\right)^{2} + \left(\dfrac{-2}{\sqrt{5}}\right)^{2} = \dfrac{1}{5} + \dfrac{4}{5} = 1$

Answer to your question is, "you don't".  Why told you that you could?

anonymous · Answer

the question is in standard position and the terminal side of theta intersects the unit circle at the point (1/rad5,-2/rad5) find sin cos and tan

tkhunny · Answer

What Quadrant is it in?

anonymous · Answer

it doesn't say

tkhunny · Answer

Yes it does.  Where does it intersect the unit circle?  That tells you.

anonymous · Answer

its in standard position and it only gives you the points i listed above

tkhunny · Answer

And that tells you the quadrant.  Come on.  You have to get this piece.

x > 0 and y < 0.  What Quadrant is it in?