Question

The quadractic x(squared) +5x-14 has what type of roots?

Answer 1

\(\large x^2 + 5x - 14\)

Answer 2

find the discriminant

Answer 3

\(\large D = \sqrt{b^2 - 4ac}\)

Answer 4

Yes , this is confusing :(

Answer 5

do you know the standard form of quadratic equation ?

Answer 6

Yes

Answer 7

\(\large ax^2 + bx + c\)

Answer 8

compare your equation with above, and figure out below :
a = ?
b = ?
c = ?

Answer 9

Got it

Answer 10

I have the discriminant but how do I figure out the roots ?

Answer 11

use below :

if \(D > 0\) then, "two different real roots"
if \(D < 0 \) then, "two different complex roots"
if \(D = 0\) then, "two SAME rational roots"

Answer 12

wat did u get for \(D\) ?

Answer 13

-31

Answer 14

nope.. try again

Answer 15

This is hard :(

Answer 16

\(\large x^2 + 5x - 14 \)

a = 1
b = 5
c = -14

Answer 17

right ?

Answer 18

Yes

Answer 19

\(\large D = \sqrt{b^2 - 4ac}\)

\(\large D = \sqrt{(5)^2 - 4(1)(-14)}\)

\(\large D = \sqrt{25 + 56}\)

\(\large D = \sqrt{81}\)

\(\large D = 9\)

Answer 20

fine ?

Answer 21

So the discriminant is 9

Answer 22

yes :)

Answer 23

so the roots are "two real roots"
but they will be "rational" because 81 is a perfect square

Answer 24

"two different rational roots"

Answer 25

let me correct a mistake ive started wid :

\(\large D = b^2 - 4ac\)

square-root sign is not there ok ?

Answer 26

Thank you ! And I just starting learning this today.. I think I should catch on

Answer 27

you wlcme :) good luck !!