WILL GIVE MEDAL.
6.Find the number of moles of HCI that were titrated.

NaOH: HCI is 1:1
so n(NaOH)=n(HCI)=0.003 moles at neurtalization.

7.calculate the concentration of HCI:
m=n/V n=0.003 mol, V=0.025L
M(HCI)=0.003 moles/0.025 L=0.12 moles/L or 0.12M

Question

WILL GIVE MEDAL.
6.Find the number of moles of HCI that were titrated.

NaOH: HCI is 1:1
so n(NaOH)=n(HCI)=0.003 moles at neurtalization.

7.calculate the concentration of HCI:
m=n/V n=0.003 mol, V=0.025L
M(HCI)=0.003 moles/0.025 L=0.12 moles/L or 0.12M

abb0t · Answer

Are you asking to check your work?

anonymous · Answer

no just to help get answers

abb0t · Answer

It looks like you already have your answers written down.

anonymous · Answer

thats just what my work sheet says, i just typed what my work sheet gave me. honestly im helping my sister try to finish her chemistry because i dont have chemistry and i dont know what to do but i know its not the answers